1-3[2(z+1)-5(z-2)]=

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Solution for 1-3[2(z+1)-5(z-2)]= equation:


Simplifying
1 + -3[2(z + 1) + -5(z + -2)] = 0

Reorder the terms:
1 + -3[2(1 + z) + -5(z + -2)] = 0
1 + -3[(1 * 2 + z * 2) + -5(z + -2)] = 0
1 + -3[(2 + 2z) + -5(z + -2)] = 0

Reorder the terms:
1 + -3[2 + 2z + -5(-2 + z)] = 0
1 + -3[2 + 2z + (-2 * -5 + z * -5)] = 0
1 + -3[2 + 2z + (10 + -5z)] = 0

Reorder the terms:
1 + -3[2 + 10 + 2z + -5z] = 0

Combine like terms: 2 + 10 = 12
1 + -3[12 + 2z + -5z] = 0

Combine like terms: 2z + -5z = -3z
1 + -3[12 + -3z] = 0
1 + [12 * -3 + -3z * -3] = 0
1 + [-36 + 9z] = 0

Combine like terms: 1 + -36 = -35
-35 + 9z = 0

Solving
-35 + 9z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '35' to each side of the equation.
-35 + 35 + 9z = 0 + 35

Combine like terms: -35 + 35 = 0
0 + 9z = 0 + 35
9z = 0 + 35

Combine like terms: 0 + 35 = 35
9z = 35

Divide each side by '9'.
z = 3.888888889

Simplifying
z = 3.888888889

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